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If two triangles have two sides and the included angle in the one equal to two sides and the included angle in the other, each to each, the two triangles will be equal.
A Treatise on Spherics: Comprising the Elements of Spherical Geometry, and ... - Pagina 146
door Daniel Cresswell - 1816 - 294 pagina’s
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## A Course of Mathematics ...: Composed for the Use of the Royal Military ...

Charles Hutton - 1811
...another. 11. Angles that have equal measures, or arcs, are equal. THEOREM I. IF two Triangles have Two Sides and the Included Angle in the one, equal to Two Sides and the Included Angle in the other, the Triangles will be Identical, or equal in aU respects. In the two triangles AEC, DEF, if the side...
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## A Course of Mathematics in Two Volumes for the Use of Academies ..., Volume 1

Charles Hutton - 1816
...one another. 11. Angles that have equal measures, or arcs, are equal. THEOREM I IF two Triangles have Two Sides and the Included Angle . in the one, equal to Two Sides and the Included Aiuile in the other, the Triangles will be Identical, or equal in all respects. , In the two triangles...
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## A Course of Mathematics: For the Use of Academies, as Well as Private ...

Charles Hutton - 1822
...Angles that have equal measures, or arcs to the same radius, are equal. THEOREM I. IF two Triangles have Two Sides and the Included Angle in the one, equal to Two Sides and the Included Angle in the other, the Triangles will be Identical, or equal in all respects. la the two triangles ABC, PEE, if the side...
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## A Course of Mathematics for the Use of Academies: As Well as ..., Volume 1

Charles Hutton - 1825
...Angles that have equal measures, or arcs to the same radios, are equal. THEOREM I. IP two Triangles have Two Sides and the Included Angle in the one, equal to Two Sides and the Included Angle in the other, the Triangles will be Identical, or equal in all respects. In the two triangles ABC, DEP, if the side...
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## Elements of Geometry: With Notes

John Radford Young - 1827 - 208 pagina’s
...the arcs AB, ED, subtending these angles are equal. Join AB, ED. Then the triangles ACB, DCE, having two sides and the included angle in the one, equal to two sides and the included angle in the other, are equal ; so that if ACB be applied to DCE, there shall be an entire coincidence, the point A coinciding...
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## Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - 1835 - 316 pagina’s
...cannot be both pa" rallel to the same 'straight line." PROPOSITION I. THEOREM. tf two triangles have two sides and the included angle in the one, equal to two sides and the included angle in the other, the triangles will be identical, or equal in all respects. Let ABC, DEF be two triangles which have...
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## Elements of Geometry and Trigonometry

Adrien Marie Legendre - 1836 - 359 pagina’s
...the angle ACB, by hypothesis ; and the side BC common : therefore, the two triangles, BDC, BAC, have two sides and the included angle in the one, equal...and the included angle in the other, each to each : hence they are equal (Prop. V.). But the part cannot be equal to the whole (Ax. 8.) ; hence, there...
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## Elements of Geometry: Containing the First Six Books of Euclid : with a ...

John Playfair - 1837 - 318 pagina’s
...arcs AFD, DGB, subtending these angles, are equal. Join AD, DB ; then the triangles ACD, BCD, having two sides and the included angle in the one, equal to two sides and the included angle in the other, are equal : so that, if ACD be applied to BCD, there shall be an entire coincidence, the point A coinciding...
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## Elements of Geometry and Trigonometry

Adrien Marie Legendre - 1838 - 359 pagina’s
...the angle ACB, by hypothesis;^/ and the side BC common : therefore, the two triangles, BDC, BAC, have two sides and the included angle in the one, equal to two sides and the included angle in (he other, each to each : hence they are equal (Prop. V.). But the part cannot be equal to the whole...
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## Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - 1842 - 317 pagina’s
...arcs AFD, DGB, subtending these angles, are equal. Join AD, DB ; then the triangles ACD, BCD, having two sides and the included angle in the one, equal to two sides and the included angle in the other, are equal : so that, if ACD be applied to BCD, there shall be an entire coincidence, the point A coinciding...
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