Greek MathematicsDover, 1963 - 552 pagina's |
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Pagina 157
... meet the circumference of that circle , since P is on the right cylinder standing on ABC as base . Let AP meet the semicircle BQE in Q , and let AC ' meet its diameter BE in N. Now both semicircles are at right angles to the plane of ...
... meet the circumference of that circle , since P is on the right cylinder standing on ABC as base . Let AP meet the semicircle BQE in Q , and let AC ' meet its diameter BE in N. Now both semicircles are at right angles to the plane of ...
Pagina 370
... meet the circle with centre C again in M , N. Then , the segments PQR , RNM being similar , the angles PQR , RNM are equal , so that NM is parallel to PF . Produce NM to meet FD in V. Then EV : EF - EM : EP EC : EA c : a ; EV : EF ...
... meet the circle with centre C again in M , N. Then , the segments PQR , RNM being similar , the angles PQR , RNM are equal , so that NM is parallel to PF . Produce NM to meet FD in V. Then EV : EF - EM : EP EC : EA c : a ; EV : EF ...
Pagina 441
... meet in H and HA be joined , then the parallelograms ABDE , ACFG are together equal to the parallelogram contained by BC , HA in an angle which is equal to the sum of the angles ABC , DHA . Produce HA to meet BC in K , draw BL , CM ...
... meet in H and HA be joined , then the parallelograms ABDE , ACFG are together equal to the parallelogram contained by BC , HA in an angle which is equal to the sum of the angles ABC , DHA . Produce HA to meet BC in K , draw BL , CM ...
Inhoudsopgave
Classification of mathematical subjects | 5 |
NUMERICAL NOTATION AND PRACTICAL CAL | 11 |
B Addition and subtraction | 28 |
Copyright | |
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algebra Apollonius Archimedes Archytas Aristotle arithmetic assumed astronomy axis base bisected Book centre of gravity chord circle circumference circumscribed cone conics construction contained cube curve cylinder definition Democritus diameter Diophantus divided draw drawn earth Elements equal equation equilateral equivalent Eratosthenes Eucl Euclid Eudemus Eudoxus Eutocius figure geometry given ratio given straight line gives gnomon Greek height Heron Hipparchus Hippocrates hyperbola inscribed irrational isosceles lemmas length loci magnitudes mathematics mean proportionals method of exhaustion moon multiple namely Nicomachus Pappus parabola parallel parallelogram pentagon perpendicular plane Plato polygon Porisms problem Proclus produced proof Prop propositions proved Ptolemy pyramid Pythagoras Pythagoreans radius rectangle respectively right angles right-angled triangle says segment semicircle sides similar solution solved sphere square number surface tangent Thales Theaetetus Theon Theon of Alexandria theorem theory tion treatise volume