| Edward Laurence - 1716 - 375 pagina’s
...external < a, is equal to t wo right Angles (by tbe^tb /)confequently all the internal and external **Angles are equal to twice as many right Angles as the Figure has** fides. But all its internal Angles are equal to twiee as many right Angles eicept 4 as it has fides... | |
| Edward Wells - 1723 - 294 pagina’s
...the Sum of all the Angles in all the Tri~ angles, into which the Figure is divided, will together be **equal to twice as ma-ny right Angles, as the Figure has Sides.** But the Angles about P, the inward Point of each Figure, wherein all the Triangles concur, are (by... | |
| Robert Simson - 1762 - 466 pagina’s
...angles CBA, BAC, ACB are equal to two right angles. wherefore if a fide of a triangle &c. Q^ED CoR. i . **All the interior angles of any rectilineal figure,...equal to twice as many right angles as the figure has** fides. For any recHlineal figure ABCDE can be divided into as many triangles as the figure has fides... | |
| Euclid, Edmund Stone - 1765 - 464 pagina’s
...(for every whole ig equal to all its parts taken together) therefore .all the angles of a right-lined **figure, together with four right angles, are equal to twice as many right angles as the figure has** fides. And taking away four right angles from each, there will remain all the angles of the figure... | |
| Thomas Malton - 1774 - 440 pagina’s
...by the Sides. ie equal to four Right Angles. And, all the internal Angles of any Right-lined Figure **are equal to twice as many Right Angles as the Figure has Sides,** wanting four, (Th. i. i0. i.) confequently, the external Angles being equal to thofe four (Th. 2. of... | |
| Robert Simson - 1775 - 520 pagina’s
...vertex of the triangles; that is", together with four right angles. Therefore all the angles of the **figure, together with four right angles, are equal to twice as many right angles as the figure has** fides. CoR. 2. All the exterior angles of any re&ilineal figure, are together equal to four right angles.... | |
| Euclid - 1781 - 520 pagina’s
...vertex of the triangles; that isa, together with four right angles. Thprefpre all the angles of the **figure, together with four right angles, are equal to twice as many right angles as the figure has** fides. CoR. 2. All the exterior angles of any rectilineal figure, arc together equal to four right... | |
| John McGregor (teacher of mathematics.) - 1792 - 431 pagina’s
...angles of any regular polygon* 3By cor. i ft, I. 32. Euclid. All the anterior angles of any reoilineal **figure, together with four right angles, are equal to twice as many right angles as the figure has** fides. Hence the following rule. RULÉ. From double thé number of fides f übt vail: 4, and the remainder... | |
| Euclid, John Playfair - 1795 - 400 pagina’s
...vertex of the triangles : that is a, together witi four right angles. Therefore all the angles of the **figure, together with four right angles, are equal to twice as many** rigit angles as the fi rurehas fides. CoR. 2. All the exterior angles of any reftilineal figure an... | |
| Alexander Ingram - 1799 - 351 pagina’s
...angles CBA, BAC, ACB are equal to two right angles. Wherefore, if a fide of a triangle, &c. Q^ED CoR. i. **All the interior angles of any rectilineal figure,...equal to twice as many right angles as the figure has** fides. For For any reftilineal figure ABCDE can be divided into as many triangles as the figure has... | |
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