 | John Keill - 1723 - 444 pagina’s
...every of the Angles KHG,HGM,GML, is equal to the Angle HKL, or KLM. Therefore the fiveAngles GHK,HKL, KLM, LMG, MGH, are equal between themfelves. And fo...equilateral, and defcribed about the Circle ABCDE j •which was to be dune. PROPOSITION XIII, PROBLEM. To tinfcribe a Circle in an equilateral and equiangular... | |
 | Robert Simson - 1762 - 488 pagina’s
...before demonftrated ; the angle HKL is equal to KLM. and in like manner it may be fliewn, that each of the angles KHG, HGM, GML is equal to the angle...therefore the five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the pentagon GHKLM is equiangular. and it is equilateral, as was demonftrated... | |
 | Euclid - 1765 - 492 pagina’s
...We demonftrate after the fame manner that the angles KHG, HGM, GML are each equal to the angles HKL, KLM: Therefore the five angles GHK, HKL, KLM, LMG, MGH are equal to one another. Wherefore the I pentagon GHK t M is equiangular. But it has alfo been proved to be... | |
 | Robert Simson - 1775 - 534 pagina’s
...the angle HKL is equal to KLM : And in like manner it may be fhewn, that each of the angles KHG, HGMi GML is equal to the angle HKL or KLM : Therefore the five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the pentagon GHKLM is equiangular : And it is et;uil.ttcr.tl, as was demonftrated... | |
 | Euclid, James Williamson - 1781 - 324 pagina’s
...manner each of the angles KHG, HGM, GML will be demonftrated to be equal to either of the angles HKL, KLM; therefore the five angles GHK, HKL, KLM, LMG, MGH are equal to one another : therefore the pentagon GHKLM is equiangular ; but it has been alfo demonftrated to... | |
 | Euclid, John Playfair - 1795 - 462 pagina’s
...before demonftrated, the angle HKL is equal to KLM : and in like manner it may be fliown, that each of the angles KHG, HGM, GML is equal to the angle...therefore the five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the pentagon GHKLM is equiangular : and it is equilateral, as was demouftrated... | |
 | Robert Simson - 1804 - 530 pagina’s
...was before demonftrated; the angle HKL is equal to KLM. and in like manner it may be fhewn, that each of the angles KHG, HGM, GML is equal to the angle...therefore the five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the pentagon GHKLM is equiangular, and it is equilateral, as was demonftrated;... | |
 | Robert Simson - 1806 - 546 pagina’s
...angle HKL is equal to KLM: and in like manner it may be shown, that each of the angles KHG, ! IG.M, GML is equal to the angle HKL or KLM : therefore the five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the pentagon GHKLM is equiangular : and it is equilateral, as -was demonstrated... | |
 | John Playfair - 1806 - 320 pagina’s
...as was before demonstrated, the angle HKL is equal to KLM. In like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL, of KLM. Therefore the Book IV. five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the... | |
 | Euclides - 1816 - 588 pagina’s
...before demonstrated, the angle HKL is equal to KLM : And in like manner it may be shown, that each of the angles KHG, HGM, GML is equal to the angle...Therefore the five angles GHK, HKL, KLM, LMG, MGH, being tqual to one another, the pentagon GHKLM is equiangular: And it is equilateral, as was demonstrated;... | |
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And in like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL or KLM ; therefore the five angles GHK, HKL, KLM, LMG, MGH... 
