 | James Thompson - 1808 - 176 pagina’s
...area of a trafiezoid, or quadrangle, <u'o cf •whose opposite sides are parallel. RULE — Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product •will be the area. EXAMPLES. 13. Required the area of a trapezoid whose parallel... | |
 | Peter Nicholson - 1809 - 426 pagina’s
...BF. 14 X36 84 42 504=the area of ABCD. PROBLEM VI. To find the area of a trapezoid. Multiply the half sum of the parallel sides by the perpendicular distance between them, and the product will be the area. EXAMPLE I. What is fhe area of a board or plank in the form of a trapeziod, being 1f. 7i. one end,... | |
 | Thomas Keith - 1817 - 306 pagina’s
...perches. PROBLEM VIII. • To find the Area of a Trapezoid. RULE *. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Example 1. Let AB c D JE. be a trapezoid, the side '-. A )•. — 23, D c = 9•5, and CI — 13,... | |
 | Matthew Iley - 1820 - 512 pagina’s
...Content, for an Inch in Depth, of a Quadrilateral having two Parallel unequal Sides. RULE. By the Pen. Multiply half the sum of the parallel sides by the perpendicular distance between them, and divide the product by the number of cubic inches in the proposed integer. By the Sliding Rule. Set... | |
 | Anthony Nesbit - 1824 - 476 pagina’s
...is its area ? Ans. 1131^.2 in. 9 pa. PROBLEM VIII. To find the area of a Irapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Or, half the sum of the sides multiplied by their distance will... | |
 | Peter Nicholson - 1825 - 1046 pagina’s
...42 501 = the arca of ABCD. MENSURATION. Prob. 6. To find the area of a trapezoid. Multiply the half sum of the parallel sides by the perpendicular distance between them, and the product will be the area. Ex. 3. What is the area of a board or plank in the form of a trapezoid, being If. 7¡- at one end,... | |
 | Zadock Thompson - 1826 - 176 pagina’s
...54.299 rods. I Problem III. Tojind the area of a trapezoid. :BuLE.— Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Examples. 1. One of the two parallel sides of a trapezoid is 7.5 chains and the other 12.25, and the... | |
 | Thomas Hornby (land surveyor.) - 1827 - 318 pagina’s
...00000000 2.40000 40 16.00000 Ans. 0A. 2n. 16p. PROBLEM 3. To find the Area of a Trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. EXAMPLE. Required the area of the trapezoid AB CD, whose parallel... | |
 | John Bonnycastle - 1829 - 256 pagina’s
...the area of a trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides AB and... | |
 | Edinburgh encyclopaedia - 1830 - 856 pagina’s
...trapezoid is a quadrilateral, of which two opposite sides are parallel but not equal. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product is the area. In the trapezoid ABCD, draw the diagonal AC, and from its extremities... | |
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To find the area of a trapezoid, multiply half the sum of the parallel sides by the perpendicular distance between them ; the product will be the area. 
