 FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of...  Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books - Pagina 183door Euclid - 1765 - 464 pagina’sVolledige weergave - Over dit boek
 | John Keill - 1723 - 444 pagina’s
...Perpendicular F K. In the fame Manner we demonstrate, that FL, FM,- or FG, is equal to FH, or F K. Therefore the five Right Lines FG, FH, FK, FL, FM, are equal to each other. And fo a Circle defcribed on the Center F, with either of the Diftances FG, FH, FK, FL,... | |
 | Euclid, John Keill - 1733 - 444 pagina’s
...Perpendicular FH equal to the Perpendicular F K. In the fame Manner we demonftrate, that FL, FM, or FG, is equal to FH, or FK. Therefore the five Right Lines FG, FH, FK, FL, FM, are equal to each other. And fo a Circle defcribed oh the Center F, with either of the Diftances FG, FH, FK, FL,... | |
 | John Keill - 1772 - 462 pagina’s
...the Perpendicular F K. In the fame manner we demonftrate, that FL, FM, or FG, is equal to FH, or F K. Therefore the five Right • Lines FG, FH, FK, FL, FM, are equal to each other, and fo a Circle defcribed on the Centre F, with either of the Diftances FG, FH, FK, FL,... | |
 | Euclid - 1781 - 552 pagina’s
...perpendicular FH is equal to the perpendicular FK : In the fame manner it may be demonftrated that FL, FM, FG are each of them equal to FH or FK ; therefore the five ftraight lines FG, FH, FK, FL, FM are equal to one another : Wherefore the cifcle defcribed from the... | |
 | Robert Simson - 1781 - 534 pagina’s
...perpendicular FH is equal to the perpendicular FK. in the fwne manner it may be demonftrated that FL, FM, FG are each of them equal to FH or FK; therefore the five ftraight lines FG, FH, FK, FL, FM are equal to one another. wherefore the circle defcribe .'. from... | |
 | Euclid, John Playfair - 1795 - 462 pagina’s
...perpendicular FH is equal to the perpendicular FK : in the fame manner it may be demonftrated, that FL, FM, FG are each of them equal to FH or FK : therefore the five ftraight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle defcribed from the... | |
 | Robert Simson - 1804 - 530 pagina’s
...perpendicular FH is equal to the perpendicular FK. in the fame manner it may be demonftrated that FL, FM, FG are each of them equal to FH or FK; therefore the five ftraight lines FG, FH, FK, FL, FM are equal to one another, wherefore the circle de~ fcribed from the... | |
 | Euclides - 1816 - 588 pagina’s
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated ; that FL, FM, FG are each of them equal to FH, or FK : Therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : Wherefore the circle described from the... | |
 | John Playfair - 1819 - 350 pagina’s
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH or FK , therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the... | |
 | Peter Nicholson - 1825 - 1046 pagina’s
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH or FK : Therefore the uve straight linei FG, FH, FK , FL, FM are equal to on* another: Wherefore the circb described from... | |
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