| Euclides - 1853 - 176 pagina’s
...making any angle with ab; and in a С take any point d, and take a С the same multiple of ad, that a Ь is of the part which is to be cut off from it : join, b С, and draw de parallel to it : then ae is the part required to be cut off. Because ed is parallel... | |
| William Somerville Orr - 1854 - 534 pagina’s
...CD. PROPOSITION IX.— PROBLEM. From a given straight line (AB) to cut off any part required. From A draw a straight line AC, making any angle with AB ; and in it take any point D ; and take AC, the same multiple of AD, that AB is of the part to be cut off. Draw... | |
| Euclides - 1855 - 230 pagina’s
...IX. PBOBLEM. From a given finite straight line (AB) to cut off any required part, or submultiple. _ SOLUTION. From the point A draw a straight line AC,...draw DE parallel to it : then AE is the part required tobecut of. DEMONSTRATION. Because ED is parallel to BC, one of the sides of the triangle ABC ; as... | |
| John Playfair - 1855 - 334 pagina’s
...; it is required to cut ofT from AB, a part which shall be contained in it a given number of times. From the point A draw a straight line AC making any angle with AB ; and in AC take any point 1), and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be... | |
| Euclides - 1860 - 288 pagina’s
...line AB ; it is required to cut off from it a part of which AB shall be a given multiple. (.Const.) From the point A draw a straight line AC making any...to it; then AE is the part required to be cut off. (Dem.) Because ED is parallel to one of the sides of the triangle ABC, namely, to BC ; CD is to DA... | |
| Robert Potts - 1860 - 380 pagina’s
...off any part required. Let AB be the given straight line. It is required to cut off any part from it. From the point A draw a straight line AC, making any...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
| Euclides - 1863 - 122 pagina’s
...DBA. BC is to BA as BA is to BD; and in the triangles ABC and ACD, BC is to CA as CA is to CD (VI. 4). From the point A draw a straight line AC, making any angle BAC with AB. In AC take any point D, and make AC the same multiple of AD that AB is of the part to... | |
| Euclides - 1864 - 448 pagina’s
...off any part required. Let AB be the given straight line. It is required to cut off any part from it. From the point A draw a straight line AC, making any...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
| Euclides - 1865 - 402 pagina’s
...vi. 2.) Let AB be the given straight line. It is required to cut off any part from it. CONSTRUCTION From the point A draw a straight line AC, making any...cut off from it ; join BC, and draw DE parallel to CB. (i. 31.) Then AB shall be the part required to he out off. DEMONSTRATION Because ED is parallel... | |
| Robert Potts - 1865 - 528 pagina’s
...part required. Let AB be the given straight line. It is required to cut off any part from it. Prom the point A draw a straight line AC, making any angle...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
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