 | Charles Reiner - 1837 - 246 pagina’s
...and be equal to it. M. — Here, then, is a third instance of equality in triangles : what is it ? angles of the one equal to two angles of the other, each to each, and have likewise the sides adjacent to the equal angles equal to each other. M. — Repeat, now, all you... | |
 | Euclides - 1837 - 112 pagina’s
...be > Z EOF. PROPOSITION XXVI. (Argument ad absurdum). Theorem. If two triangles have two angles of one equal to two angles of the other, each to each, and one side equal to one side; viz., either the sides adjacent to the equal angles, or opposite to the equal angles... | |
 | Andrew Bell - 1837 - 290 pagina’s
...the angles GMK, GMN, are both right angles by construction ; wherefore the triangles GMK, GMN, have two angles of the one equal to two angles of the other, and they have also the side GM common ; therefore they arc equal, and the side KM is equal to the side... | |
 | A. Bell - 1837 - 180 pagina’s
...Def. 7)i and therefore the angles AFG, AEG, are also equal. The triangles AGE, AGF, have therefore two angles of the one equal to two angles of the other, and they have also the side AG common ; wherefore they are equal, and the side AF is equal to the side... | |
 | Euclid, James Thomson - 1837 - 410 pagina’s
...equal (const.) to FBD, and that the right angles BED, BFD are equal, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
 | William Whewell - 1837 - 226 pagina’s
...therefore MLN is equal to LKH; and the angles at H and at N are right angles. Therefore the triangles have two angles of the one equal to two angles of the other ; and the side KL is equal to LM. Therefore the triangles are equal, and HL is equal to MN; that is,... | |
 | Euclides - 1838 - 264 pagina’s
...right angle FCK is equal to the right angle FCL ; therefore, in the two triangles FKC, FLC, there are two angles of the one equal to two angles of the other, each to each ; and the side FC, which is adjacent to the equal angles in each, is common to both ; therefore «„ , the... | |
 | Thomas Kerigan - 1838 - 804 pagina’s
...the angle BCD, by the aforesaid proposition. And because the two triangles ADF and BCF have, thus, two angles of the one equal to two angles of the other, viz., the angle FAD to the angle FB C, and the angle AD F to the angle BCF; and the side AF of the... | |
 | Robert Simson - 1838 - 434 pagina’s
...by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each is common to both ; therefore... | |
 | Euclides - 1841 - 378 pagina’s
...15. 1. angle EBC: and the angle AEG is equal* to the angle BEH; therefore the triangles AEG, BEH have two angles of the one equal to two angles of the other, each to each, and the sides AE, EB, adjacent to the equal angles, equal to one another: therefore their other * 28. 1.... | |
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If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. 
