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" Therefore all the interior angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. "
The Young Gentleman's Arithmetick, and Geometry: Containing Such Elements of ... - Pagina 209
door Edward Wells - 1723 - 294 pagina’s
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A Treatise on Land-surveying: Comprising the Theory Developed from Five ...

William Mitchell Gillespie - 1857 - 524 pagina’s
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles is equal to twice as many right angles, as the figure has sides less two ; since the figure can be divided into that number of triangles. Hence this common rule. "...
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Elements of Geometry and Conic Sections

Elias Loomis - 1858 - 234 pagina’s
...that is, together with four right angles (Prop. V., Cor. 2). Therefore the angles of the polygon are equal to twice as many right angles as the figure has sides, wanting four right angles. Cor. 1. The sum of the angles of a quadrilateral is four right angles ;...
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The Practice of Engineering Field Work, Applied to Land, Hydrographic, and ...

W. Davis Haskoll - 1858 - 324 pagina’s
...and in an irregular polygon they may be all unequal. The interior angles of a polygon are together equal to twice as many right angles as the figure has sides, less four. On this is based the theory of the traverse, of which further explanation will be given...
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Elements of Geometry, and Plane and Spherical Trigonometry: With Numerous ...

Horatio Nelson Robinson - 1860 - 453 pagina’s
...triangles is equal to two right angles, (Th. 11) ; and the sum of the angles of all the triangles must be equal to twice as many right angles as the figure has sides. But the sum of these angles contains the sum of four right angles about the point p ; taking these away, and...
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Euclid's Elements of plane geometry [book 1-6] explicitly enunciated, by J ...

Euclides - 1860
...polygon be produced to meet, the sum of the salient angles thus formed, with eight right angles, will be equal to twice as many right angles as the figure has sides. Let ABCDE be a polygon, and let its sides produced meet in F, G, H, T, K ; then the sum of the salient...
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The examination papers as set for the preliminary literary examination of ...

Royal college of surgeons of England - 1860
...two right angles ; and all the angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 6. The opposite sides and angles of parallelograms are equal to one another, and the diameter bisects...
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Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1860 - 361 pagina’s
...figure together with four right angles ; but it has been proved that the angles of the triangles are equal to twice as many right angles as the figure has sides ; therefore all the angles of the figure together with four right angles, are equal to twice as many...
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The Mathematical Monthly, Volume 2

1860
...must be aliquot parts of the circle or of four right angles. All the angles of any such figure are equal to twice as many right angles as the figure has sides minus four right angles, or if be the number of sides, the sum of all the angles is (2n — 4) right...
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Queen's scholarship examination. Amner's eight years' scholarship questions ...

Joseph Wollman - 1879
...Corollary 1. — The interior angles of any rectilineal figure together with four right angles are equal to twice as many right angles as the figure has sides. The angles of a regular hexagon + 4 right angles = 12 right angles ; .-. The angles of a regular hexagon...
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Moffatt's pupil teachers' course (ed. by T. Page). Candidates, 2nd (-4th) year

Moffatt and Paige - 1879
...together with four right angles. But it has been proved that all the angles of all these triangles are equal to twice as many right angles as the figure has sides. Therefore all the angles of the figure, together with four right angles, are equal to twice as many...
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