| William Mitchell Gillespie - 1857 - 524 pagina’s
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles is **equal to twice as many right angles, as the figure has sides** less two ; since the figure can be divided into that number of triangles. Hence this common rule. "... | |
| Elias Loomis - 1858 - 234 pagina’s
...that is, together with four right angles (Prop. V., Cor. 2). Therefore the angles of the polygon are **equal to twice as many right angles as the figure has sides,** wanting four right angles. Cor. 1. The sum of the angles of a quadrilateral is four right angles ;... | |
| W. Davis Haskoll - 1858 - 324 pagina’s
...and in an irregular polygon they may be all unequal. The interior angles of a polygon are together **equal to twice as many right angles as the figure has sides,** less four. On this is based the theory of the traverse, of which further explanation will be given... | |
| Horatio Nelson Robinson - 1860 - 453 pagina’s
...triangles is equal to two right angles, (Th. 11) ; and the sum of the angles of all the triangles must **be equal to twice as many right angles as the figure has sides. But the** sum of these angles contains the sum of four right angles about the point p ; taking these away, and... | |
| Euclides - 1860
...polygon be produced to meet, the sum of the salient angles thus formed, with eight right angles, will **be equal to twice as many right angles as the figure has sides.** Let ABCDE be a polygon, and let its sides produced meet in F, G, H, T, K ; then the sum of the salient... | |
| Royal college of surgeons of England - 1860
...two right angles ; and all the angles of any rectilineal figure, together with four right angles, are **equal to twice as many right angles as the figure has sides.** 6. The opposite sides and angles of parallelograms are equal to one another, and the diameter bisects... | |
| Robert Potts - 1860 - 361 pagina’s
...figure together with four right angles ; but it has been proved that the angles of the triangles are **equal to twice as many right angles as the figure has sides** ; therefore all the angles of the figure together with four right angles, are equal to twice as many... | |
| 1860
...must be aliquot parts of the circle or of four right angles. All the angles of any such figure are **equal to twice as many right angles as the figure has sides** minus four right angles, or if « be the number of sides, the sum of all the angles is (2n — 4) right... | |
| Joseph Wollman - 1879
...Corollary 1. — The interior angles of any rectilineal figure together with four right angles are **equal to twice as many right angles as the figure has sides.** The angles of a regular hexagon + 4 right angles = 12 right angles ; .-. The angles of a regular hexagon... | |
| Moffatt and Paige - 1879
...together with four right angles. But it has been proved that all the angles of all these triangles are **equal to twice as many right angles as the figure has sides.** Therefore all the angles of the figure, together with four right angles, are equal to twice as many... | |
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