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" TO a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle. "
Easy Introduction to Mathematics - Pagina 255
door Charles Butler - 1814
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Civil service guide

Robert Johnston (F.R.G.S.) - 1869 - 178 pagina’s
...digits ; find the number. Pure Mathematics. 1. To a given straight line apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a rectilineal angle. 2. A segment of a circle being given, describe the circle of which it is the segment....
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Elements of geometry, containing the first two (third and fourth ..., Deel 1

Euclides - 1871
...its opposite sides, are together half of the parallelogram. 5—2 To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given angle. a Let ABC be the given A , and D the given L . It is required to describe ar~l equal to A ABC,...
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The first and second books of Euclid explained to beginners, by C.P. Mason

Euclid, Charles Peter Mason - 1872
...double of the AABE, which is equal to the AABD. PEOPOSITION XLU. To describe a parallelogram, that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle. For the construction necessary in this proposition we must be able, — 1. To join two given points...
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Elements of geometry, containing books i. to vi.and portions of books xi ...

Euclides, James Hamblin Smith - 1872 - 349 pagina’s
...are together half of the parallelogram. PROPOSITION XLII. PROBLEM. To describe a parallelogram that shall be equal to a given triangle, and have one of its a..gles equal to a given angle. B JJ C Let ABC be the given A , and D the given L . It is required...
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The Acting Teacher's and Student's in Training Guide and Text Book for ...

Henry Major - 1873
...two equal parts ; wherefore ABCD is also double of EBC. XLII. — To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle. Let ABC be the given triangle, and D the given rectilineal angle. Bisect BC in E, join AE, and at the...
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Pure mathematics, Volume 1

Edward Atkins - 1874
...complements, &c. QED Proposition 44. — Problem. To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle. It is required to apply to the straight line AB a parallelogram equal to the triangle C, and having...
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The Elements of Euclid, containing the first six books, with a selection of ...

Euclides - 1874
...parallelogram and a triangle, &c. QED PROPOSITION 42. — Problem. To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle. Let ABC be the given triangle, and D the given rectilineal angle. It is required to describe a parallelogram...
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A school Euclid, being books i. & ii. of Euclid's Elements, with notes by C ...

Euclides - 1874
...rectangle having the same baae and altitude. PROPOSITION 42. PROBLEM. To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle. * Let ABC be the given triangle, and D the given ' • rectilineal angle : it is required to describe...
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Recent military, naval, and civil service examination papers in mathematics ...

Braithwaite Arnett - 1874
...same parallels, are equal to one another. 4. To a given straight line apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle. 5. Define a rhombus, and show that its opposite angles are equal. 6. If a straight line be drawn through...
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Pure Mathematics, Volume 1

Edward Atkins - 1874
...&c. QED Proposition 44. — Problem. To a given straight line to apply a parallelogram, which thall be equal to a, given triangle, and have one of its angles equal to a given rectilineal angle. GEOMETRY. Make paralleloI.Tam BEFG = A < ', and / at li = i D, and EBAa straight line. HBandFE meet....
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