 | Robert Potts - 1855 - 1050 pagina’s
...be drawn to intersect one another, the greater segments will be equal to the sides of the pentagon. 3. If two triangles have two angles of the one equal to two angles of the other, and one side equal to one side, viz. either the sides adjacent to the equal angles in each, or the... | |
 | Euclides - 1855 - 230 pagina’s
...the angle EBC (4): and the angle AEG is equal to the angle BEH (a); therefore the triangles AEG, BEH have two angles of the one, equal to two angles of the other, each to each, and the sides AE, EB, adjacent to the equal angles, equal to one another; wherefore they have their other... | |
 | John Playfair - 1855 - 334 pagina’s
...it is not equal to it: therefore the angle BAC is greater than the angle EDF. PROP. XXVI. THLOR. Jf two triangles have two angles of the one equal to two angles of the otIirr, each to each; and one side equal to one side, viz. either the sides adjacent to the equal anglrs,... | |
 | Cambridge univ, exam. papers - 1856 - 200 pagina’s
...another, on the same side of it, are either two right angles, or are together equal to two right angles. 3. If two triangles have two angles of the one equal...to two angles of the other, each to each, and one si ie equal to one side, via. the sides opposite to equal angles in each, then shall the other sides... | |
 | Peter Nicholson - 1856 - 518 pagina’s
...parallel to CD, the alternate angles, GFE, FGH, are also equal ; therefore the two triangles GEF, HFG, have two angles of the one equal to two angles of the other, each to each ; and the side FG, adjacent to the equal angles, common ; the triangles are therefore equal (theorem 6) ;... | |
 | Euclides - 1856 - 168 pagina’s
...BAC, and the angle ABE is equal to the angle ABC (being both right angles), the triangles ABC, ABE have two angles of the one equal to two angles of the other, and the side AB common to the two. Therefore the triangles ABC, ABE are equal, and the side AE is equal... | |
 | Elias Loomis - 1857 - 242 pagina’s
...is parallel to CD, the alternate angles GHE, HEF are also equal. Therefore, the triangles HEF, EHG have two angles of the one equal to two angles of the other, each to each, and the side Eli included between the equal angles, common ; hence the triangles are equal (Prop. VII.)... | |
 | Adrien Marie Legendre, Charles Davies - 1857 - 442 pagina’s
...consequently, the two equiangular triangles BA C, CUD, are similar figures. Cor. Two triangles which have two angles of the one equal to two angles of the other, are similar; for, the third angles are then equal, and the two triangles are equian gular (BI, p. 25,... | |
 | Edward Mann Langley, W. Seys Phillips - 1890 - 538 pagina’s
...the obverse of Prop. 8. From what Proposition is it an immediate inference ? PROPOSITION 26. THEOREM. If two triangles have two angles of the one equal...each to each, and one side equal to one side, namely, either the sides adjacent to the equal angles or sides which are opposite to equal angles in each,... | |
 | Euclid - 1890 - 442 pagina’s
...necessitates that BC < EF. AA It remains .'. that A > D. Proposition 26. (First Part.) THEOREM — If two triangles have two angles of the one equal to two angles of the other, each to each, and have likewise the two sides adjacent to these angles equal ; then the triangles are identically equal,... | |
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If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal... 
