 | Edward Atkins - 1876 - 130 pagina’s
...(Const.), and DE is common to the two triangles ADE, CDE, The two sides AD, DE are equal to the two sides CD, DE, each to each; And the angle ADE is equal to the angle CDE, for each of them is a right angle (Const.); I Therefore the base EA is equal to the base EC (I. 4). But EA was shewn... | |
 | Isaac Todhunter - 1880 - 426 pagina’s
...DE is common to the two triangles ADE, CDE ; the two sides AD, DE are equal to the two sides CD,DE, each to each; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; [Construction. therefore the base EA is equal to the base EC. [I. 4. But EA was... | |
 | Euclides - 1881 - 236 pagina’s
...triangles ADE and CDE, the two sides AD and DE, are equal to the two sides CD and DE, each to each. But the angle ADE is -equal to the angle CDE, for each of them (Const.) is a right angle. Therefore the bage AE is equal (I 4) to the base fc. C. But AE was shown... | |
 | Euclid, Isaac Todhunter - 1883 - 428 pagina’s
...[Construction. and DE is common to the two triangles ADE, CDE ; the two sides AD, DE are equal to the two sides CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; " [Construction. therefore the base EA is equal to the base EC. [I. 4. But EA was... | |
 | Euclid - 1908 - 456 pagina’s
...equal to DC, and DE is common, the two sides AD, DE are equal to the two sides CD, DE respectively ; and the angle ADE is equal to the angle CDE, for each is right ; therefore the base AE is equal to the base CE. But AE was proved equal to BE ; therefore... | |
 | Euclid - 452 pagina’s
...equal to DC, and DE is common, the two sides AD, DE are equal to the two sides CD, DE respectively ; and the angle ADE is equal to the angle CDE, for each is right ; therefore the base AE is equal to the base CE. But AE was proved equal to BE ; therefore... | |
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EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal... 
