| Euclides - 1834
...Again, because the angle at B is half a right angle, and FOB •29.1. a right angle, for it is equal* **to the interior and opposite angle ECB, the remaining...the angle at B is equal to the angle BFD, and the** • 6. 1• side DF to * the side DB. And because AC is equal to CE, the square of AC is equal to the... | |
| Euclid, Robert Simson - 1835 - 513 pagina’s
...side GF: Again, because the angle at B is half a right angle, and FDB a right angle, for it is equal6 **to the interior and opposite angle ECB, the remaining...at B is equal to the angle BFD, and the side DF to** f the side DB : And because AC is equal to CE, the square of AC is equal to the square of CE ; therefore... | |
| John Playfair - 1837 - 318 pagina’s
...angle GEF is half a right angle, and EGF a right angle, for it is equal (29. 1.) to the interior and **opposite angle ECB, the remaining angle EFG is half...EF2=EG2+GF2; therefore, EF2=2GF2 =2CD2, because (34.** 1.) CD=GF. And it was shown that AE2=2AC2 ; therefore AE2+EF2=2AC2+2CD3. But (47. 1.) AF2=AE2+ EF2,... | |
| Andrew Bell - 1837 - 240 pagina’s
...(I. 6). Again, because the angle at B is half a right angle, and FDB a right angle, for it is equal **to the interior and opposite angle ECB, the remaining...at B is equal to the angle BFD, and the side DF to** the side DB. Now, because AC is equal to CE, the square of AC is equal to the square of CE ; therefore... | |
| Euclid - 1838 - 416 pagina’s
...EG equal (6. 1.) to the side GF: again, because the angle at B is half a right angle, and FDB half **a right angle, for it is equal (29. 1.) to the interior...angle BFD, and the side DF to (6. 1.) the side DB:** and because AC is equal to CE, the square of AC is equal to the square of CE ; therefore the squares... | |
| Euclid - 1838 - 416 pagina’s
...right angle, for it is equal (29. 1.) to the interior and opposite angle ECB, the remaining angle BFDis **half a right angle ; therefore the angle at B is equal...angle BFD, and the side DF to (6. 1.) the side DB:** and because AC is equal to CE, the square of AC is equal to the square of CE ; therefore the squares... | |
| Euclides - 1838
...Again, because the angle at B is half a right angle, and *29. i. FDB a right angle, for it is equal* **to the interior and opposite angle ECB, the remaining...is half a right angle : therefore the angle at B is** *6. i. equal to the angle BFD, and the side DF to* the side DB. And because AC is equal to CE, the... | |
| Euclides - 1841
...FDB a right angle, for it is * 29. 1. equal* to the interior and opposite angle ECB, theretherefore **the angle at B is equal to the angle BFD, and the side DF to*** the side DB. And because AC * 6 - 1. is equal to CE, the square of AC is equal to the square of CE;... | |
| John Playfair - 1842 - 317 pagina’s
...angle GEF is half a right angle, and EGF a right angle, for it is equal (29. 1.) to the interior and **opposite angle ECB, the remaining angle EFG is half...1.)CD=GF. And it was shown that AE2=2AC2; therefore** AE2+EF2=2AC2+2CD2. But (47. 1.) AF2=AE2+EF2, and AD2+DF2= AF2, or AD2+DB2=AF2 ; therefore, also, AD2-f-DB2=... | |
| Euclides - 1842
...equal to the angle EFG, and the side EG equal (6.1.) to the side GF. Again: because the angle at в **is half a right angle, and FDB a right angle, for...BFD is half a right angle ; therefore the angle at** в is equal to the angle BFD, and the side DF (6. 1.) to the side DB: and because AC is equal to CE,... | |
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