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Boeken Boek 21 - 30 van 56 over Again, because the angle at B is half a right angle, and FDB a right angle, for it....
" Again, because the angle at B is half a right angle, and FDB a right angle, for it is equal... "
Elements of Geometry: Containing the First Six Books of Euclid with a ... - Pagina 55
door John Playfair - 1855 - 318 pagina’s
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The Elements of Euclid; viz. the first six books, together with the eleventh ...

Euclides - 1834
...Again, because the angle at B is half a right angle, and FOB •29.1. a right angle, for it is equal* to the interior and opposite angle ECB, the remaining...the angle at B is equal to the angle BFD, and the • 6. 1• side DF to * the side DB. And because AC is equal to CE, the square of AC is equal to the...
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The Elements of Euclid: viz. the first six books, together with the eleventh ...

Euclid, Robert Simson - 1835 - 513 pagina’s
...side GF: Again, because the angle at B is half a right angle, and FDB a right angle, for it is equal6 to the interior and opposite angle ECB, the remaining...at B is equal to the angle BFD, and the side DF to f the side DB : And because AC is equal to CE, the square of AC is equal to the square of CE ; therefore...
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Elements of Geometry: Containing the First Six Books of Euclid : with a ...

John Playfair - 1837 - 318 pagina’s
...angle GEF is half a right angle, and EGF a right angle, for it is equal (29. 1.) to the interior and opposite angle ECB, the remaining angle EFG is half...EF2=EG2+GF2; therefore, EF2=2GF2 =2CD2, because (34. 1.) CD=GF. And it was shown that AE2=2AC2 ; therefore AE2+EF2=2AC2+2CD3. But (47. 1.) AF2=AE2+ EF2,...
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Elements of Plane Geometry According to Euclid

Andrew Bell - 1837 - 240 pagina’s
...(I. 6). Again, because the angle at B is half a right angle, and FDB a right angle, for it is equal to the interior and opposite angle ECB, the remaining...at B is equal to the angle BFD, and the side DF to the side DB. Now, because AC is equal to CE, the square of AC is equal to the square of CE ; therefore...
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The Elements of Euclid

Euclid - 1838 - 416 pagina’s
...EG equal (6. 1.) to the side GF: again, because the angle at B is half a right angle, and FDB half a right angle, for it is equal (29. 1.) to the interior...angle BFD, and the side DF to (6. 1.) the side DB: and because AC is equal to CE, the square of AC is equal to the square of CE ; therefore the squares...
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The Elements of Euclid

Euclid - 1838 - 416 pagina’s
...right angle, for it is equal (29. 1.) to the interior and opposite angle ECB, the remaining angle BFDis half a right angle ; therefore the angle at B is equal...angle BFD, and the side DF to (6. 1.) the side DB: and because AC is equal to CE, the square of AC is equal to the square of CE ; therefore the squares...
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Euclid's Elements [book 1-6] with corrections, by J.R. Young

Euclides - 1838
...Again, because the angle at B is half a right angle, and *29. i. FDB a right angle, for it is equal* to the interior and opposite angle ECB, the remaining...is half a right angle : therefore the angle at B is *6. i. equal to the angle BFD, and the side DF to* the side DB. And because AC is equal to CE, the...
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The Elements of Euclid; viz. the first six books,together with the eleventh ...

Euclides - 1841
...FDB a right angle, for it is * 29. 1. equal* to the interior and opposite angle ECB, theretherefore the angle at B is equal to the angle BFD, and the side DF to* the side DB. And because AC * 6 - 1. is equal to CE, the square of AC is equal to the square of CE;...
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Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - 1842 - 317 pagina’s
...angle GEF is half a right angle, and EGF a right angle, for it is equal (29. 1.) to the interior and opposite angle ECB, the remaining angle EFG is half...1.)CD=GF. And it was shown that AE2=2AC2; therefore AE2+EF2=2AC2+2CD2. But (47. 1.) AF2=AE2+EF2, and AD2+DF2= AF2, or AD2+DB2=AF2 ; therefore, also, AD2-f-DB2=...
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Elements of geometry: consisting of the first four,and the sixth, books of ...

Euclides - 1842
...equal to the angle EFG, and the side EG equal (6.1.) to the side GF. Again: because the angle at в is half a right angle, and FDB a right angle, for...BFD is half a right angle ; therefore the angle at в is equal to the angle BFD, and the side DF (6. 1.) to the side DB: and because AC is equal to CE,...
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