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 Boeken Boek 41 - 50 van 55 over Again, because the angle at B is half a right angle, and FDB a right angle, for it....
Again, because the angle at B is half a right angle, and FDB a right angle, for it is equal...
Elements of Geometry: Containing the First Six Books of Euclid with a ... - Pagina 55
door John Playfair - 1855 - 318 pagina’s
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Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1860 - 361 pagina’s
...and opposite angle ECB, (l. 29.) therefore the remaining angle BID is half a right angle ; wherefore the angle at B is equal to the angle BFD, and the side DF equal to the side DB. (l. 6.) And because AC is equal to CE, the square on ACia equal to the square...
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The school Euclid: comprising the first four books, by A.K. Isbister

Euclides - 1862
...right angle, and FDB a right angle, for it is equal to the interior and opposite angle ECB, (1.29) the remaining angle BFD is half a right angle ; therefore the angle at B is equal to the angle BFD, wherefore tlie side DF is equal to the side DB. (i. 6.) therefore the squares of AC, CE, are double...
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Euclid's Elements of geometry, books i. ii. iii. iv

Euclides - 1862
...interior and opposite angle ECB, (I. 29.) 10. Therefore the remaining angle BFD is half a right angle. 11. Therefore the angle at B is equal to the angle BFD, and the side DF is equal to the side DB. (I. 6.) 12. And because AC is equal to CE (const.), the square on AC is equal...
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The elements of plane geometry; or, The first six books of Euclid, ed. by W ...

Euclides - 1863
...interior and opposite angle ECB; therefore the remaining angle BFD is half a right angle. Wherefore the angle at B is equal to the angle BFD, and the side DI? (I. 0) to the side DB. Because AC is equal to CE, the square of AC is equal to the square of CE....
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Euclid's Elements of geometry, the first four books, by R. Potts. Corrected ...

Robert Potts - 1864
...and opposite angle ECB, (l. 29.) therefore the remaining angle BFD is half a right angle ; wherefore the angle at B is equal to the angle BFD, and the side DF equal to the side D B. (l. 6.) And because AC is equal to CE, the square on AC is equal to the square...
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The college Euclid: comprising the first six and the parts of the eleventh ...

...right angle, and FDB a right angle, for it is equal to the interior and opposite angle ECB, (i. 29) the remaining angle BFD is half a right angle ; therefore the angle at B is equal to the angle BFD, wherefore the side DF is equal to the side DB. (i. 6.) And because AC is equal to CE, the square of...
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The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1867 - 400 pagina’s
...angle FDB a right angle, for it is equal to the interior and opposite angle ECB ; [I. 29. therefore the remaining angle BFD is half a right angle. Therefore...angle at B is equal to the angle BFD, and the side DF is equal to the side DB. " [I. 6. And because AC is equal to CE, [Construction. the square on AC is...
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The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1867 - 400 pagina’s
...angle FDB a right angle, for it is equal to the interior and opposite angle ECB ; [I. 29. therefore the remaining angle BFD is half a right angle. Therefore...angle at B is equal to the angle BFD, and the side DF is equal to the side DB. [I. 6. And because AC is equal to CE, [Construction. the square on AC is equal...
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Pure Mathematics, Volume 1

1874
...angle FDB a right angle, for it is equal to the interior and opposite angle ECB (I. 29), Therefore the remaining angle BFD is half a right angle ; Therefore...angle at B is equal to the angle BFD, and the side DF is equal to the side DB (I. 6). And because AC is equal to CE (Const.), the square on AC is equal to...
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A school Euclid, being books i. & ii. of Euclid's Elements, with notes by C ...

Charles Mansford - 1874
...angle FDB a right angle, for it is equal to the interior and opposite angle ECB . [I*. 29.] therefore the remaining angle BFD is half a right angle. Therefore...the angle at B is equal to the angle BFD, and the aide DP is equal to the side DB. [I. 6.] And because AC is equal to CE, [Const.] the square on AC is...
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