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" If the errors are alike, divide the difference of the products by the difference of the errors, and the quotient will be the answer. "
The Young Gentleman's Arithmetick, and Geometry: Containing Such Elements of ... - Pagina 145
door Edward Wells - 1723 - 294 pagina’s
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Mercantile Arith

Michael Walsh - 1831 - 348 pagina’s
...them crosswise. 3. If the errors are alike, that is, both greater or both less than the given number, divide the difference of the products by the difference of the errors, and the quotient is the answer ; but if the errors be unlike, divide the sum of the products by the...
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The Arithmetical Manual

Samuel Read Hall - 1832 - 294 pagina’s
...last supposed number by the first error. If both supposed numbers are either too large or too small, divide the difference of the products by the difference of the errors. But if one is too large and the other too small, divide the sum of the products by the sum of the errors,...
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The Youth's Assistant in Theorhetic [sic] and Practical Arithmetic: Designed ...

Zadock Thompson - 1832 - 182 pagina’s
...numher by the first error ; and if the errors he alike (that is, both too great or both too small), divide the difference of the products by the difference of the errors ; but if unlike, divide the sum of the products by the sum of the errors, and the quotient will be the answer....
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The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for ...

Zadock Thompson - 1832 - 186 pagina’s
...number by the first error ; and if the errors be alike (that is, both too great or both too small), divide the difference of the products by the difference of the errors ; but if unlike, divide the sum of the products by the sum of the errors, and the quotient will be the answer....
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A system of practical arithmetic, comprehending numerous rules and examples ...

Samuel YOUNG (of Manchester.) - 1833 - 272 pagina’s
...position, then if the errors be of the same kind, that is, both less or both greater than the given number, divide the difference of the Products by the difference of the Errors ; but if the one error is greater and the other less than the given number, divide the sum of the Products by the...
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A New System of Arithmetic, on the Cancelling Plan: Embracing the Rules of ...

Charles Guilford Burnham - 1837 - 266 pagina’s
...supposition by the first error. III. If the errors are alike — that is, both too great or both too small, divide the difference of the products by the difference of the errors. IV. If the errors are unlike — that is, one too large, and the other too small, divide the sum of...
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The Mercantile Arithmetic: Adapted to the Commerece of the United States, in ...

Michael Walsh - 1838 - 346 pagina’s
...them crosswise. 3. If the errors are alike, that is, both greater or both less than the given number, divide the difference of the products by the difference of the errors, and the quotient is the answer ; but if the errors be unlike, divide the sum of the products by the...
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The National Arithmetic, on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - 1839 - 356 pagina’s
...by the contra supposition, and find the sum and difference of the products. If the errors are alike, divide the difference of the products by the difference of the errors, and the quotient will be the answer. If the errors are unlike, divide the sum of the products by the...
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United States Calculator: Or, Arithmetic Simplified

John M'Nevin - 1841 - 300 pagina’s
...or both signs —, subtract, but when one sign is + and the other — add. If the errors are alike, divide the difference of the products by the difference of the errors; but, if unlike, divide the sum of the products by the sum of the errors. 1. Divide 15 into 2 such parts, so...
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The United States Calculator: Or, Arithmetic Simplified, in Dollars and ...

John M'Nevin - 1841 - 300 pagina’s
...or both signs — , subtract, but when one sign is + and the other — add, If the errors are alike, divide the difference of the products by the difference of the errors; but, if unlike, divide the sum of the products by the sum of the errors. 1. Divide 15 into 2 such parts, so...
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