 | Roswell Chamberlain Smith - 1841 - 324 pagina’s
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16 Double the root (quotient) for a partial divisor, and on its right, place, for the total... | |
 | Charles Guilford Burnham - 1841 - 324 pagina’s
...the left hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to 'the remainder bring down the next period, for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the quotient... | |
 | Roswell Chamberlain Smith - 1842 - 320 pagina’s
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total... | |
 | Roswell Chamberlain Smith - 1843 - 320 pagina’s
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total... | |
 | John Darby (teacher of mathematics.) - 1843 - 236 pagina’s
...first or left hand period, and put its root for a quotient. Subtract this square number from the first period, and to the remainder bring down the next period for a dividend. 5. Double the quotient figure, for the first portion of the divisor ; then find what figure... | |
 | Charles Haynes Haswell - 1844 - 298 pagina’s
...left-hand period, and plnce Its root in the quotient; subtrnct the square number from the left-hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor ; find how many times the divisor is contained... | |
 | 1845 - 210 pagina’s
...period, and set its root on the right of the given number: subtract said square from the left hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and try how often this divisor (with the figure used in... | |
 | Almon Ticknor - 1846 - 276 pagina’s
...place <he root to the right of the given number, and subtract the cube of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Square the root, and multiply it by three for a defective divisor. 4. Reserve mentally... | |
 | James Bates Thomson - 1846 - 354 pagina’s
...placing its root on the right of the number for the first figure of the root, subtract its cube from the period, and to the remainder bring down the next period for a dividend. III. Square the root already found, giving it its true local value ; multiply this square... | |
 | James Bates Thomson - 1846 - 362 pagina’s
...2 on the right of the given number for tke first figure in the root, we subtract its cube from the period, and to the remainder bring down the next period for a dividend. This shows that we have 7625 solid feet to be added to the cubical mound already found. 3.... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... 
