 | Benjamin Greenleaf - 1861 - 338 pagina’s
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. RULE. — Separate the given number into as many periods as possible of three figures each,... | |
 | Daniel Adams - 1861 - 452 pagina’s
...period, and write its root as a quotient in division. Subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... | |
 | John Flint (inspector of schools.) - 1862 - 152 pagina’s
...period, and write its cube root as the first figure of the root. Subtract its cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the part of the root found by 300 for a trial divisor ; divide the... | |
 | Benjamin Greenleaf - 1863 - 338 pagina’s
...the left-hand period, and place its root on the right ; subtract the cube of this root from the first period, and to the remainder bring down the next period for a dividend. At the left of the dividend write three times the square ofth* root already found, for a... | |
 | Horatio Nelson Robinson - 1863 - 432 pagina’s
...wríte its root for the first figure in the root sought ; subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write twice the first figure, of the root, for a trial divisor... | |
 | George Augustus Walton - 1864 - 376 pagina’s
...period, and write its root as the first term in the answer. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. Take twice the root already found for a trial divisor ; rejecting the right hand figure of... | |
 | George Augustus Walton - 1864 - 364 pagina’s
...hand period, and write its root as the first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor.... | |
 | Horatio Nelson Robinson - 1866 - 328 pagina’s
...root for the first figure in the required root ; subtract the square of this figure from the first period, and to the remainder bring down the -next period for a dividend. III. Double the root already found, and write the result on the left for a divisor ; find... | |
 | Joseph Ray - 1866 - 420 pagina’s
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Square the root already found, and multiply it by 3 for a trial divisor. Find how many... | |
 | Joseph Ray - 1866 - 250 pagina’s
...the right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and place it on the left for a divisor. Find how many times... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... 
